physica

a stone is thrown vertically upward with an initial velocity v0. the distance travelled by it in time 1.5v0/g?

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  1. recall that the motion of the stone is uniformly accelerated motion (because it accelerated due to gravity). thus we can use the formula:
    h = vo*t - 1/2(g)(t^2)
    where
    h = height
    vo = initial velocity
    t = time
    g = acceleration due to gravity = 9.8 m/s^2
    substituting,
    h = vo*(1.5*vo/g) - (1/2)(g)(1.5*vo/g)^2
    h = 1.5*[(vo)^2]/g - 1.125*[(vo)^2]/g
    h = 0.375*[(vo)^2]/g

    hope this helps~ :)

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    posted by Jai

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