calculus iii

What heading (or direction) and airspeed (speed in still air) are required for an airplane to fly 837 mph due north if a wind of 63 mph is blowing in the direction of S 11.5 degrees E?

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asked by miles
  1. The information translated into triangle ABC,
    where BC is vertical and magnitude 837
    AB is our required vector
    and angle C = 168.5°

    by cosine law
    |AB|^2 = 837^2 + 63^2 - 2(837)(63)cos 168.5°
    |AB| = 898.82

    by sine law:
    Sin B / 63 = sin168.5/898.82
    sinB = .013974
    B = .8 °

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    posted by Reiny

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