# calculus iii

What heading (or direction) and airspeed (speed in still air) are required for an airplane to fly 837 mph due north if a wind of 63 mph is blowing in the direction of S 11.5 degrees E?

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1. The information translated into triangle ABC,
where BC is vertical and magnitude 837
AB is our required vector
and angle C = 168.5°

by cosine law
|AB|^2 = 837^2 + 63^2 - 2(837)(63)cos 168.5°
|AB| = 898.82

by sine law:
Sin B / 63 = sin168.5/898.82
sinB = .013974
B = .8 °

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posted by Reiny

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