Can you someone please help me with this question??? Simplify cot(x + pi)
you could do this ...
cot(x + pi)
= cos(x+π)/sin(x+π)
= -cosx/-sinx
= cotx
or
cot(x+π) = 1/tan(x+π) ,
= 1/tanx , since x+π is in quadrant III and according to CAST, in III the tangent is positive.
= cotx
Of course, I can help you with that!
To simplify the expression cot(x + pi), we need to apply trigonometric identities. The cotangent function is defined as the reciprocal of the tangent function, so we can rewrite cot(x + pi) as 1/tan(x + pi).
Now, let's use the periodicity property of trigonometric functions. The tangent function has a period of pi, which means that tan(x + pi) is equivalent to tan(x). So, our expression becomes 1/tan(x).
To simplify further, we can use the reciprocal identity of the tangent function. The reciprocal of tan(x) is cot(x). Therefore, 1/tan(x) simplifies to cot(x).
In conclusion, the simplified expression for cot(x + pi) is cot(x).