CHEMISTRY

WHAT WILL BE THE WAVELENGTH OF OXYGEN
MOLECULE IN PICOMETERS MOVING WITH A VELOCITY OF 660m/sec?...

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asked by Deepa
  1. 18.8 pm

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    posted by Samantha
  2. m=32×10^-3kg/6.02×10^23
    = 1pm =10^-12m

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  3. V=660 m/s ; h=6.626*10^-34 ;
    m = 32*10^-3÷6.02*10^23
    Lambda=h÷(mv)
    Lambda=18.8 pm
    1pm = 10^-12 m

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    posted by Nazmiya
  4. A moving electron has 4.9 into 10 power minus 25 joules of kinetic energy find out its De Broglie wavelength

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