Calculus

Find the volume of the solid obtained by rotating the region enclosed by the graphs of y=15-x, y=3x+11 and x=0 about the y-axis.

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asked by Al
  1. Find out where the curves y = 15-x and y = 3x + 11 intersect
    15 -x = 3x + 11.
    4x = 4
    x = 1. At that point, y = 14.
    The enclosed volume goes from the y axis to x = 1. You are rotating a triangle about the y axis. The limits of integration are from y = 11 to y = 15. Those are the maximum and minimum y values of the enclosed volume.

    Do an integration of
    2 pi x^2 dy from y=11 to y=14, using the y = 3x + 11 function, and add the integral of 2 pi x^2 dy from y=14 to y = 15, using the y = 15 -x function. You will have to convert x to y in those integrations, using the appropriate formula.

    It's a lot easier to visualize if you draw a figure, but I can't do that here.

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    posted by drwls

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