in the reaction 2Na + Cl2 --> 2NaCl how many grams of NaCl are produced when 25 g. of sodium reacts completely to form NaCl?

To solve this problem, we need to use stoichiometry. The balanced equation tells us that 2 moles of sodium react with 1 mole of chlorine gas to produce 2 moles of sodium chloride.

Step 1: Calculate the molar mass of sodium chloride (NaCl):
The molar mass of Na = 22.99 g/mol.
The molar mass of Cl = 35.45 g/mol.
The molar mass of NaCl = (22.99 g/mol) + (35.45 g/mol) = 58.44 g/mol.

Step 2: Convert the mass of sodium (given in the problem) to moles:
Given mass of sodium = 25 g.
Number of moles of sodium = (Given mass of sodium) / (Molar mass of sodium)
Number of moles of sodium = 25 g / 22.99 g/mol ≈ 1.09 mol.

Step 3: Use stoichiometry to find the moles of sodium chloride produced:
From the balanced equation, we know that 2 moles of sodium produce 2 moles of sodium chloride.
So, 1.09 moles of sodium will produce 1.09 moles of sodium chloride.

Step 4: Convert moles of sodium chloride to grams:
Mass of sodium chloride = (Number of moles of sodium chloride) × (Molar mass of sodium chloride)
Mass of sodium chloride = 1.09 mol × 58.44 g/mol ≈ 63.69 g.

Therefore, approximately 63.69 grams of NaCl are produced when 25 grams of sodium react completely.

To determine the number of grams of NaCl produced when 25 g of sodium (Na) reacts completely with chlorine (Cl2) to form NaCl, we need to follow a few steps:

Step 1: Determine the molar mass of the substances involved:
- The molar mass of Na is 22.99 g/mol.
- The molar mass of Cl2 is 70.90 g/mol.
- The molar mass of NaCl is 58.44 g/mol.

Step 2: Convert the mass of sodium (Na) to moles:
Using the formula:
moles = mass / molar mass,
we can calculate the moles of Na:
moles of Na = 25 g / 22.99 g/mol = 1.087 moles (rounded to three decimal places).

Since the balanced equation shows that 2 moles of Na react to produce 2 moles of NaCl, we can say that 1.087 moles of Na will produce an equal amount of NaCl.

Step 3: Convert the moles of NaCl to grams:
Since the molar mass of NaCl is 58.44 g/mol, we can calculate the mass of NaCl formed:
mass of NaCl = moles of NaCl × molar mass of NaCl.
mass of NaCl = 1.087 mol × 58.44 g/mol = 63.5 g (rounded to one decimal place).

Therefore, when 25 g of sodium (Na) reacts completely, approximately 63.5 grams of NaCl are produced.

first thing to do here is to balance the chemical equation.

2Na + Cl2 --> 2NaCl
then we get the masses of Sodium and Chlorine from periodic table of elements in order to calculate the molar mass of NaCl. from periodic table,
Na = 23
Cl = 35.5
thus, NaCl = 23+35.5 = 58.5 g/mol
therefore,
25 g Na * (1 mol Na / 23 g Na) * (2 mol NaCl / 2 mol Na) * (58.5 g NaCl / 1 mol NaCl) = 63.57 g NaCl

note that the ratio (2 mol NaCl / 2 mol Na) came from the balanced chemical reaction.

hope this helps~ :)