The instantaneous rate of appearance of water from the reaction
4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(g)
at some moment in time is 21.3 mmHg per minute. What is the instantaneous rate of disappearance of NH3 at the same moment in time?
10.7 mmHg/min
14.2 mmHg/min
21.3 mmHg/min
32.0 mmHg/min
none of these
its not 21.3 nor 10.7
6/4 = 21.3/x
solve for x.
14.2 mmHg/min
To determine the instantaneous rate of disappearance of NH3 at the same moment in time, we need to look at the balanced chemical equation for the reaction:
4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(g)
The coefficients in the balanced equation can be used as a ratio to determine the rates of reactant consumption or product formation.
In this case, the ratio of NH3 to H2O in the balanced equation is 4:6, which simplifies to 2:3. This means that for every 2 moles of NH3 consumed, 3 moles of H2O are produced.
Given that the instantaneous rate of appearance of water (H2O) is 21.3 mmHg per minute, we can determine the rate of disappearance of NH3 by using the ratio of 2:3.
21.3 mmHg/min * (2 moles NH3 / 3 moles H2O)
= 14.2 mmHg/min
Therefore, the instantaneous rate of disappearance of NH3 at the same moment in time is 14.2 mmHg/min.
The correct answer is 14.2 mmHg/min.