physics

A ball is thrown vertically upward with a speed of +12.0 m/s.


How long does the ball take to hit the ground after it reaches its highest point?


What is its velocity when it returns to the level from which it started?

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asked by anne
  1. Well, the easy way is to say the average speed of the ball on the awy up is (12 + 0) / 2 = 6 m/s

    Now how high did it go?
    (1/2) m v^2 = m g h
    144/2 = 9.8 h
    h = 7.35 meters up
    so
    6 t = 7.35
    t = 1.22 seconds

    part 2 is trivial, same speed down as up but opposite direction, -12 m/s

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    posted by Damon

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