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Math
Write the first trigonometric function in terms of the second for θ in the given quadrant. tan(θ), cos(θ); θ in Quadrant IV I believe to start this is 1/cos^2*theta. Am I write? If not, can you please help me?! -
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1. Let (-7, 4) be a point on the terminal side of (theta). Find the exact values of sin(theta), csc(theta), and cot(theta). 2. Let (theta) be an angle in quadrant IV such that sin(theta)=-2/5. Find the exact values of sec(theta) -
trig
The terminal side of θ lies on a given line in the specified quadrant. Find the values of the six trigonometric functions of θ by finding a point on the line. Line: (55/48)x Quadrant:III sin(θ)= cos(θ)= tan(θ)= csc(θ)= -
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evaluate the expression under the given conditions. cos(θ − ϕ); cos(θ) = 5/13, θ in Quadrant IV, tan(ϕ) = − square root15,ϕ in Quadrant II Anyone know how to do this I have never been this confused in my life
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Pre calc
Find sin(2x), cos(2x), and tan(2x) from the given information. sin(x) = 5/13, x in Quadrant I sin(2x)? cos(2x)? tan(2x)? I honeslty just need one good example of how to do these please show all work and finalize answer -
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If tan A= 3/4 and cos B=-5/13, where A and B are both third-quadrant angles, find sin(A+B). Please explain how you found all the answers -
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tan(θ + ϕ); cos(θ) = − 1/3 θ in Quadrant III, sin(ϕ) = 1/4 ϕ in Quadrant II I am really struggling with this idk why I keep getting the wrong answers -
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If θ is an angle in standard position and tan θ = −7/2, in which quadrant can θ be located? a. quadrant 3 and quadrant 4 b. quadrant 2 and quadrant 4 c. quadrant 2 and quadrant 3 d. quadrant 1 and quadrant 2
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trig math
If θ is an angle in standard position and tan θ = −7/2, in which quadrant can θ be located? a. quadrant 3 and quadrant 4 b. quadrant 2 and quadrant 4 c. quadrant 2 and quadrant 3 d. quadrant 1 and quadrant 2 help -
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Find the values of sin θ, cos θ, and tan θ for the given right triangle (in the link below). Give the exact values. www.webassign.net/aufexc2/8-5-003.gif sin θ= cos θ= tan θ= my answer is c^2 = a^2 +b^2 c^2 = 5^2+12^2 c^2 = -
precalc
tan(θ + ϕ); cos(θ) = − 1/3 θ in Quadrant III, sin(ϕ) = 1/4 ϕ in Quadrant II evaluate the expression -
trig
Angle θ lies in the second quadrant, and sin θ = 3/5. Find cos θ and tan θ.
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