# Algebra II Please check-

Please help-What is the equation of the ellipse with foci (0,6), (0,-6) and co-vertices (2,0),(-2,0)

Please explain the steps because I have 5 to do for homework-Thank you-I'm really stuck on this
I thought the answer would be x^2/4 + y^2/40 = 1 but that can't be because the choices are:
x^2/1 + y^2/40 = 1 or x^2/1 + y^2/36
I'm really confused

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asked by Jodi
1. I forgot to put that I think b= 2
c=6, so therefore
a^2-2^2 = 6^2
so a= 40, that' how I got to my equation

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posted by Jodi
2. Your answer is correct.

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posted by Mgraph
3. It can't be correct my equation because that isn't a choice I was given-that's what I don't understand-thanks for trying to help though

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posted by Jodi
4. Jodi,my answer was exactly identical to
yours.

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posted by Henry

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