Members of the Lake Shawnee club pay $40 per summer season plus $7.50 each time they rent a boat. Nonmembers pay $12.50 each time they rent a boat. How many times would both a member and a nonmember have to rent a boat in order to pay the same amount?
40 + 7.5 x = 12.5 x
40 = 5 x
x = 8 times
To find the number of times that both a member and a nonmember would have to rent a boat in order to pay the same amount, we can set up an equation.
Let's assume the number of times they rent a boat is represented by "x".
For a member, the total cost is $40 for the summer season plus $7.50 per boat rental. So, the total cost for a member would be:
Total cost for a member = $40 + ($7.50 * x)
For a nonmember, the cost is $12.50 per boat rental. So, the total cost for a nonmember would be:
Total cost for a nonmember = $12.50 * x
Now, to find the number of times they would have to rent a boat to pay the same amount, we can set up an equation:
$40 + ($7.50 * x) = $12.50 * x
Now we can solve this equation:
$40 + $7.50x = $12.50x
Subtract $7.50x from both sides:
$40 = $12.50x - $7.50x
Combine like terms:
$40 = $5.00x
Now divide both sides by $5.00:
$40 / $5.00 = x
8 = x
Therefore, both a member and a nonmember would have to rent a boat 8 times in order to pay the same amount.
To determine the number of times a member and a nonmember would have to rent a boat to pay the same amount, we'll set up an equation.
Let's assume the number of times both a member and a nonmember rent a boat is represented by "x."
For a member:
Total cost = Membership cost + Boat rental cost
Total cost = $40 + $7.50x
For a nonmember:
Total cost = Boat rental cost
Total cost = $12.50x
Since we want the total cost to be the same for both a member and a nonmember, we can equate the two equations:
$40 + $7.50x = $12.50x
Now, we can solve for "x":
$40 = $12.50x - $7.50x
$40 = $5x
Dividing both sides by $5, we find that:
$x = 8
Therefore, both a member and a nonmember would have to rent a boat 8 times in order to pay the same amount.