A quantity of sulfuric acid is added to 100. mL of water. The final volume of the solution is 111 mL and has a density of 1.14 g/mL. What mass of acid was added? Assume the density of the water is 1.00 g/mL.
1.14 g/mL x 111 mL = 126.5 grams soln
100 mL H2O x 1.00 g/mL = 100 grams
difference is 26.5 grams.
To find the mass of the acid that was added, we need to first determine the mass of the solution, and then subtract the mass of the water present in the solution. Here's how to calculate it:
Step 1: Calculate the mass of the solution:
Mass of solution = density of solution x volume of solution
Given that the density of the solution is 1.14 g/mL and the final volume of the solution is 111 mL, we can calculate the mass of the solution:
Mass of solution = 1.14 g/mL x 111 mL = 126.54 g
Step 2: Calculate the mass of the water in the solution:
Mass of water = density of water x volume of water
Given that the density of water is 1.00 g/mL and the volume of water is 100 mL, we can calculate the mass of water:
Mass of water = 1.00 g/mL x 100 mL = 100.00 g
Step 3: Calculate the mass of the acid:
Mass of acid = Mass of solution - Mass of water
Mass of acid = 126.54 g - 100.00 g = 26.54 g
Therefore, the mass of the acid that was added is 26.54 grams.