You have 3.00 L of a 2.37 M solution of NaCl(aq) called solution A. You also have 2.00 L of a 2.00 M solution of AgNO3(aq) called solution B. You mix these solutions together, making solution C.

Calculate the concentration (in M) of Na+ ions in solution C.

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  1. The sodium ion is a spectator ion in this reaction, i.e. it does not take part. Thus we can ignore the chemistry.

    Number of moles at start

    3.00 L x 2.37 mole L^-1

    Because 1 mole of NaCl gives 1 mole of Na+ in solution.

    volume at end = 3.00 L + 2.00 L
    =5.00 L

    so concentration of Na+ at end is
    =3.00 L x 2.37 mole L^-1/5.00 L

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  2. 1.162

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