
 👍 0
 👎 0
posted by Mgraph 
 👍 0
 👎 0
posted by kate 
 👍 0
 👎 0
posted by kate 
 👍 0
 👎 0
posted by kate 
 👍 0
 👎 0
posted by Mgraph
Respond to this Question
Similar Questions

Integration
Intergrate ¡ì sec^3(x) dx could anybody please check this answer. are the steps correct? thanks. = ¡ì sec x d tan x = sec x tan x  ¡ì tan x d sec x = sec x tan x  ¡ì sec x tan^2(x) dx = sec x tan x + ¡ì sec x dx  ¡ì
asked by Vidal on October 15, 2006 
calculus (check my work please)
Not sure if it is right, I have check with the answer in the book and a few integral calculators but they seem to get a different answer ∫ sec^3(x)tan^3(x) dx ∫ sec^3(x)tan(x)(sec^2(x)1) dx ∫ tan(x)sec(x)[sec^4(x)sec^2(x)]
asked by Jay on June 7, 2012 
Calculus 12th grade (double check my work please)
2 given the curve is described by the equation r=3cos ¥è, find the angle that the tangent line makes with the radius vector when ¥è=120¨¬. A. 30¨¬ B. 45¨¬ C. 60¨¬ D. 90¨¬ not sure A or D 2.) which of the following
asked by anon on March 6, 2011 
calculus
find dy/dx y=ln (secx + tanx) Let u= secx + tan x dy/dx= 1/u * du/dx now, put the derivative of d secx/dx + dtanx/dx in. You may have some challenging algebra to simplify it. Use the chain rule. Let y(u) = ln u u(x) = sec x + tan
asked by amy on March 9, 2007 
Calculus AP
I'm doing trigonometric integrals i wanted to know im doing step is my answer right? ∫ tan^3 (2x) sec^5(2x) dx =∫ tan^2(2x) sec^4(2x) tan*sec(2x) dx =∫ (sec^2(2x)1)sec^4 tan*sec(2x) dx let u=sec x, du= 1/2 tan*sec(2x) dx
asked by Vicky on September 22, 2012 
calculus
So I am suppose to evaulate this problem y=tan^4(2x) and I am confused. my friend did this : 3 tan ^4 (2x) d sec^ 2x (2x)= 6 tan ^4 (2x) d sec^2 (2x) She says it's right but what confuses me is she deriving the 4 and made it a
asked by Anonymous on July 28, 2012 
Calculus
could anybody please explain how sec x tan x  ¡ì sec x tan^2(x) dx = sec x tan x + ¡ì sec x dx  ¡ì sec^3(x) dx What I don't understand about your question is what is ¡ì ? i just want to know if those two equations are
asked by Rain on October 16, 2006 
more trig.... how fun!!!!
if you can't help me with my first question hopw you can help me with this one. sec(x)/csc(x)=tan(x) thanx to anyone who can help From the definition of the sec and csc functions, and the tan function, sec(x)/csc(x) =
asked by berhana on November 6, 2006 
Calculus 12th grade (double check my work please)
1.) which of the following represents dy/dx when y=e^2x Sec(3x)? A.3e^2x sec(3x) tan (3x)2e^2x Sec(3x)
asked by anon on March 7, 2011 
Calculus PLEASE check my work ,
1.) which of the following represents dy/dx when y=e^2x Sec(3x)? A.3e^2x sec(3x) tan (3x)2e^2x Sec(3x)
asked by anon on March 12, 2011 
calculus
Use integration by parts to evaluate the integral of x*sec^2(3x). My answer is ([x*tan(3x)]/3)[ln(sec(3x))/9] but it's incorrect. u=x dv=sec^2(3x)dx du=dx v=(1/3)tan(3x) [xtan(3x)]/3  integral of(1/3)tan(3x)dx 
asked by Integration by Parts on August 30, 2008