# MATHS

Evaluate with the help of Logarithms 1) 2391/3072 2.38*3.901/4.83

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1. let x = 2391/3072 2.38*3.901/4.83
log x = log (2391/3072 2.38*3.901/4.83)
= log(2391) - log(3072) + log(2.38) + log(3.901) - log(4.83)
= 0.17496
x = 1.496

my calculator answer: 1.496 to 3 decimals

This is the kind of question I actually taught about 45 years ago.
In those days we had Log-tables that were only correct to about 3 decimals.
To do the question the way I typed it, I actually used my calculator to get the log values.
Today, such a question would only have significance from a historical viewpoint.
Are you still given log tables?
If not, how does your teacher expect you to do this without tables?

This type of question is similar to asking a carpenter today to build a piece of furniture without any power tools.

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posted by Reiny

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