Solve for x.
3^(2x)-2*3^(x+5)+3^10= 0

asked by Paul
  1. I can see it as being factored to

    (3^x - 3^5)(3^x - 3^5) = 0

    so 3^x - 3^5 = 0
    3^x = 3^5

    x = 5

    posted by Reiny
  2. Rewrite the given equation using the substitutions x=rcos@ and y=rsin@. (@=theta)
    Simplify your answer.

    posted by Alex
  3. (2x-3)*(x^2+9)*(x+5)=0

    posted by Ermek

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