solve this equation:
4x^3-4x^2+13x-6=0
note: that's suppose to be 4x to the third and 4x squared
After several tries I found a factor
(2x-1)(2x^2 - x + 6) = 0
x = 1/2 or x = (1 ±√-47)/4 or (1 ±i√47)/4
4x^3-4x^2+13x-6=0
note: that's suppose to be 4x to the third and 4x squared
(2x-1)(2x^2 - x + 6) = 0
x = 1/2 or x = (1 ±√-47)/4 or (1 ±i√47)/4