Calculus

How would you solve this differential equation?

dy/dx=1/2x+y-1

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  1. It is not clear whether the equation is
    dy/dx = 1/(2x+y-1)
    or
    dy/dx = x/2 + y -1 (as you have written)

    Please clarify.

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    posted by MathMate
  2. x/2 + y - 1

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    posted by Steve

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