Chemistry

The cloth shroud from around a mummy is found to have a carbon-14 activity of 8.1 disintegrations per minute per gram of carbon as compared with living organisms that undergo 15.2 disintegrations per minute per gram of carbon.

From the half-life for carbon-14 decay, 5715 yr, calculate the age of the shroud.

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  1. k = 0.693/t1/2
    k = 0.693/5715yr = 1.213E-4
    Substitute k into the below equation.
    ln(No/N) = kt
    No = 15.2
    N = 8.1
    k from above.
    Solve for t (in years).

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    posted by DrBob222
  2. Thanks.

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  3. gttgttyujntf

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