If 25 ml of bromine, a liquid element at room temperature, is added to 100ml of water, what would be the resulting molar concentration of bromine?
To calculate the molar concentration of bromine in this solution, we need to know the number of moles of bromine and the total volume of the solution.
First, we need to convert the volume of bromine from milliliters to liters. Since there are 1000 milliliters in a liter, we divide the volume of bromine (25 mL) by 1000 to get 0.025 L.
Next, we need to determine the number of moles of bromine. To do this, we use the equation:
moles = volume (in liters) × concentration
However, we are given the volume of bromine, not the concentration. To find the concentration, we need to divide the moles of bromine by the volume of water.
Since the volume of water is 100 mL, we convert it to liters by dividing by 1000, which gives 0.1 L.
Now, we can calculate the molar concentration:
concentration = moles / volume
Substituting the values we have:
concentration = moles (bromine) / volume (water)
= (0.025 L × ? mol/L) / 0.1 L
We still need to determine the number of moles of bromine. To do this, we use the molar mass of bromine, which is approximately 79.90 g/mol.
mass = moles × molar mass
Rearranging the equation:
moles = mass / molar mass
We are given the volume of bromine (25 mL), not the mass. However, we can assume that the density of bromine is close to 3.1 g/mL. This means that the mass of 25 mL of bromine is:
mass = volume (bromine) × density (bromine)
= 25 mL × 3.1 g/mL
Now we can calculate the moles of bromine:
moles = mass / molar mass
= (25 mL × 3.1 g/mL) / 79.90 g/mol
Once we have the moles of bromine, we can substitute it back into the concentration equation to find the molar concentration of bromine.
Please note that the density assumption and molar mass used in this explanation are approximations and may vary slightly in reality.