# DrBOB222... the moles

This is what i did thus far

I wrote the eqn and i sed

1 mole of LiOH = 24g
x mole = 1 g
cross multiply

the # of moles = 0.042mol

The ratio between LiOH and CO2 is 2 : 1

i'm lost there

0.042 mols LiOH is correct.
You have the ratio of LiOH to CO2. Just multiply by the coefficients. Note that the way I do it cancels the mols LiOH and leaves mols CO2. In other words, it cancels the unit we don't want (mols LiOH) and leaves the unit we want (mols CO2). That is the way we convert mols LiOH to mols CO2.
0.42 mols LiOH x (1 mol CO2/2 mols LiOH) = ??. I simply used the coefficients in the balanced equation for the 1 and the 2).
Can you take it from here? You need to convert mols CO2 to g CO2.

so its

0.042*24(1*44/2*24) = 0.924 moles

1 mole = 44
0.924 mole = x
x= 40.66g

No. I don't understand where you came up with all of the numbers.
mols LiOH = g/molar mass or
1 g LiOH x (1 mol LiOH/24 g LiOH) = 0.0417 mols LiOH.

Now convert mols LiOH to mols CO2.
mols CO2 = 0.0417 x (1 mol CO2/2 mol LiOH) = 0.0417 x 1/2 = 0.0208 CO2.

Now convert mols CO2 to g CO2.
g CO2 = mols CO2 x molar mass CO2 =
0.0208 mols CO2 x (44 g CO2/1 mol CO2) =
0.917 g CO2.

Let me know if you don't understand but please be specific.

I GOT IT!!!!!!!

Just worded it different

Just said
the ratio between the LiOH and CO2 is 2 : 1

So u need 1/2 the amnt of LiOH

so

1/2 * 0.0417 = 0.0208 moles

and then

0.0208* 44= 0.915 g

Basically the same thing

THANKS AGAIN!!
REALLY APPRECIATE IT!

Now for the other question

Part of the SO2 that is introduced into the atmosphere by combustion of sulfur containing compounds ends up beingh converted to sulfuric acid.

2SO2 (g) + O2 (g) ---> 2H2SO4 (aq)

How much sulfuric acid can be formed from 5 moles of SO2, 2 moles of O2 and an unlimited quantity of water?

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2. 👎 0
3. 👁 188

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