what is the complete electron configuration and the abbreviated electron configuration of copper (II) ion?
what is the complete electron configuration and the abbreviated electron configuration of bromide ion?
29Cu = 1s2 2s2 2p6 3s2 3p6 3d9
[Ar] 3d9
Here is a link that describes the process very well.
http://www.mpcfaculty.net/mark_bishop/abbreviated_electron_configuration_help.htm
what this (ar)3d10 3s2 4p3
To determine the electron configuration of an element or ion, we need to know its atomic number.
1. Copper (II) Ion:
The atomic number of copper is 29, and when it forms a +2 ion, it loses two electrons.
The complete electron configuration of Copper (II) ion can be determined by following these steps:
1. Write the electron configuration of the neutral copper atom: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹ 3d¹⁰.
2. Remove two electrons from the highest energy level, which is 4s¹.
Therefore, the complete electron configuration of the Copper (II) ion is: 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰.
The abbreviated electron configuration of Copper (II) ion can be written as: [Ar] 3d¹⁰.
2. Bromide Ion:
Bromine belongs to the halogen group with an atomic number of 35. When bromine forms an ion, it gains one electron.
The complete electron configuration of Bromide ion can be determined by following these steps:
1. Write the electron configuration of the neutral bromine atom: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁵.
2. Add one electron at the highest available energy level, which is 4p⁵.
Therefore, the complete electron configuration of the Bromide ion is: 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶.
The abbreviated electron configuration of Bromide ion can be written as: [Kr] 4d¹⁰ 5s² 5p⁶.