Algebra 1

In triangle ABC ,if <A and <B are acute angles, and sin A=10/13 what is the value of cos A?

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  1. sinA = 10/13.
    This is assumed to be a rt triangle.
    sinA = 10/13 = Y/r,
    X^2+Y^2 = r^2,
    X^2+(10)^2 = (13)^2,
    x^2 = 169-100 = 69,
    X = 8.3.

    cosA = X/r = 8.3/13.

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