calc

What is the derivative of:

2pi^2r^4

would it simply be 8pi^2r^3?

I was thinking the 2pi^2 is simply the equivalent of a constant in front of the r^4 and so you would just use the power rule.

  1. 👍 0
  2. 👎 0
  3. 👁 201

Respond to this Question

First Name

Your Response

Similar Questions

  1. Calculus

    Consider the curve defined by y + cosy = x +1 for 0 =< y =< 2pi.... a. Find dy/dx in terms of y. *I got 1/(y-siny) but I feel like that's wrong. b. Write an equation for each vertical tangent to the curve. c. find d^2y/dx^2 in

  2. Calculus

    A piece of wire 40cm long is cut into two pieces. One piece is bent into the shape of a square and the other is bent into the shape of a circle. How should the wire be cut so that the total area enclosed is a) a maximum? /b) a

  3. Algebra 1

    1) what is the simplified form of (x-2)(2x+3)? Use the distributive property. A) 2x^2-x-6 B) 2x^2-6 C)2x^2-7x-6 D) 2x^2 +x-6**** 2) what is the simplified form of (3x+2)(4x-3) use a table. A)12x^2+18x+6 B) 12x^2+x-6 C)

  4. math

    Find the coterminal angles for 8pi/3. I found one: 8pi/3 - 2pi= 2pi/3 My textbook says that I should add subtract 4pi to find the other one and I'm very confused as to how you know what to add/ subtract.

  1. Math

    Prove that sin 13pi/3.sin 8pi/3+cos 2pi/3.sin 5pi /6=1/2.

  2. Math

    Find a negative and a positive coterminal angle for Ө = 2pi/3. -4pi/3 and 8pi/3

  3. calc

    i did this problem and it isn't working out, so i think i'm either making a dumb mistake or misunderstanding what it's asking. A particle moves along the x axis so that its velocity at any time t greater than or equal to 0 is

  4. Calculus

    The region enclosed by the graph of y = x^2 , the line x = 2, and the x-axis is revolved abut the y-axis. The volume of the solid generated is: A. 8pi B. 32pi/5 C. 16pi/3 D. 4pi 5. 8pi/3 I solved for x as √y and set up this

  1. Algebra 2

    Find the values of the inverse function in radians. sin^-1(0.65) a. 0.71+2pi n and -0.71+2pi n b. 0.71+2pi n and -3.85+2pi n c. 0.86+2pi n and -0.86 +2pi n d. -0.61+2pi n and 2.54+2pi n 2. tan^-1(0.09) a.-0.09+2pi n b. no such

  2. Calculus

    Find the interval(s) where the function is increasing where and it is decreasing. f(x)=sin(x+(pi/2)) for 0≤x≤2pi so my derivative is f'(x)=cos(x+(pi/2))? and my critical number is -pi/2?

  3. math please help!!

    The depth d of water in a tank oscillates sinusoidally once every 4 hours. If the smallest depth is 7.9 feet and the largest depth is 10.1 feet, find a possible formula for the depth in terms of time t in hours. (Let the water

  4. trig

    determine the solutions for tanxcos^2x-tanx=0 in the interval XE[-2pi,2pi] Ok, please describe the steps to me that you used to solve this! thank you

You can view more similar questions or ask a new question.