a pizza has a radius of 9inches. the pizza is divided into sections. one of the section has a central angle with a measure of 60 degrees wat is da area of this section of pizza?

what happens to the area of the sector if u double the central angel?

how much greater in feet is the circumference of path B then path A? leave the answer in pie
path B is the outer circle, path A is the inner circle, the radius for path A is 20ft and the radius for path B is 35ft and c=2pie r

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To find the area of a sector of a pizza, we can use the formula:

Area of Sector = (θ/360) * π * r^2

where θ is the central angle measured in degrees, π is a mathematical constant approximately equal to 3.14, and r is the radius of the pizza.

1. Given that the radius of the pizza is 9 inches and the central angle is 60 degrees, we can plug these values into the formula:

Area of Sector = (60/360) * π * 9^2
= (1/6) * 3.14 * 81
≈ 42.39 square inches

So, the area of this particular section of the pizza is approximately 42.39 square inches.

2. If we double the central angle from 60 degrees to 120 degrees, let's calculate the new area of the sector:

Area of Sector = (120/360) * π * 9^2
= (1/3) * 3.14 * 81
≈ 84.78 square inches

By doubling the central angle, the area of the sector has also doubled. Therefore, the area of the sector increases.

3. To find the difference in circumference between Path B and Path A, we can use the formula for the circumference of a circle:

Circumference = 2πr

For Path A with a radius of 20 ft, the circumference is:

Circumference of Path A = 2π * 20
= 40π ft

For Path B with a radius of 35 ft, the circumference is:

Circumference of Path B = 2π * 35
= 70π ft

To find the difference in circumference, we subtract the circumference of Path A from Path B:

Difference in Circumference = Circumference of Path B - Circumference of Path A
= (70π - 40π) ft
= 30π ft

So, the difference in circumference between Path B and Path A is 30π feet.