calculus

limit of (|x+h|-|x|)/h as h goes to 0 at x=4

why is the answer 1?

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  1. observe that we can further simplify (|x+h|-|x|)/h to
    (x + h - x)/h
    (h)/h
    1
    rewriting,
    lim 1 as h->0 at x = 4 is equal to 1, since the limit of a constant is also equal to that constant.

    hope this helps~ :)

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  2. thank you, i got it

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