precalc

solve the system of equations:
x^(2)+y^(2) = 12
xy = -4

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  1. Use substitution.

    y = -4/x

    x^2 + 16/x^2 = 12

    let u = x^2

    u + 16/u = 12
    u^2 -12u + 16 = 0

    u = (1/2)[12 +/-sqrt80]
    = 10.47 or 1.527
    x = +/-1.236 or +/-3.236
    Get y for each x using
    y = -4/x

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