# precalc

solve the system of equations:
x^(2)+y^(2) = 12
xy = -4

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1. Use substitution.

y = -4/x

x^2 + 16/x^2 = 12

let u = x^2

u + 16/u = 12
u^2 -12u + 16 = 0

u = (1/2)[12 +/-sqrt80]
= 10.47 or 1.527
x = +/-1.236 or +/-3.236
Get y for each x using
y = -4/x

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