Find the x coordinates of all relative extreme points of
f(x)=1/4x^4 + 2/3x^3- 3/2x^2 + 4

f'(x)=x^3 + 2x^2 - 3x = 0

(x^2 + 3)(x-1) = 0

x=-3 x=1 x=0 Is this correct?

1. 👍
2. 👎
3. 👁
1. I don't fully understand your problem,
but your solution to the cubic Eq is
correct.

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2. 👎

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