How do i solve using the elimination method. If the system has no solution or an infinite number of solutions, state this.
2x + 10y = 58
-14x + 8y = 140
In google type:
Solver Solving a System of Linear Equations by Elimination
When you see list of results click on:
Solver Solving a System of Linear Equations by Elimination/Addition
When page be open in rectacangles type your coefficients
1 row 2 10 58
2 row -14 8 140
and click option Solve
You will see solution step by step
To solve the system of equations using the elimination method, you need to eliminate one variable by multiplying one or both equations by certain multiples so that when you add or subtract the equations, one of the variables cancels out.
Let's solve the system of equations:
1. Multiply the first equation by 7 and the second equation by 2 to make the coefficients of x equal in both equations:
7(2x + 10y) = 7(58)
2(-14x + 8y) = 2(140)
Simplifying these equations gives:
14x + 70y = 406
-28x + 16y = 280
2. Now you have two equations with the same coefficient for x, so you can add the equations to eliminate x:
(14x + 70y) + (-28x + 16y) = 406 + 280
Simplifying this equation gives:
-12y = 686
3. Solve for y by dividing both sides by -12:
y = -686 / -12
y = 57.17
4. Substitute the value of y back into one of the original equations to solve for x. Let's use the first equation:
2x + 10(57.17) = 58
Simplifying this equation gives:
2x + 571.7 = 58
2x = -513.7
x = -256.85
So, the solution to the system of equations is x = -256.85 and y = 57.17.
This system of equations has a unique solution since there is only one x and one y value that satisfy both equations.