A cannon of mass 200kg, fires a cannonball with a mass of 10kg. The cannon ball leaves the barrel of the cannon with a velocity of 60 m/s. Using the law of conservation of momentum , explain what happens to the cannon when the cannon ball is fired. (Answer should include calculation.)

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  1. Well, I guess this cannon is fired horizontally.

    final momentum = 200 v + 10 *60 = initial momentum = 0
    v = - 600/200 = -3 m/s

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  2. Why is it 200v ??Is the formula used :
    m1v2+m2v2=(m1+m2)v ???


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  3. Pbefore = Pafter
    (m1v2)+(m2v2) = (m1v2)+(m2v2)

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