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When 90 kJ is removed from a 2-kg copper bar its temperature drops from 200 degrees celcius to 85 degrees celcius what is the specific heat of the iron?

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  1. Q = M*C*(delta T)

    Solve for C, with

    deltaT = -115 C
    Q = -90 kJ
    M = 2.0 kg

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  2. 0.391

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  3. 0.39 kJ/kg degree C

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