what is the molar solubility of barium fluoride in 0.15M NaF at 25 degrees C?

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  1. BaF2 ==> Ba^+2 + 2F^-
    S = solubility

    NaF ==> Na^+ + F^-

    Ksp = (Ba^+2)(F^-)^2 =
    (S)(S+0.15)^2 = Ksp. Solve for S.

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  2. This is almost correct, except it should be (s)(2s+.15)^2=Ksp

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