physics

an object is observed to fall from a bridge, striking the water below 3.03s ...with what velocitydid it strike the water?what was the average velocity during the fall?how high is the bridge?

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  1. "with what velocity did it strike the water?"
    final velocity = initial velocity+ (acceleration * time)
    initial velocity is zero because it fell off a bridge.
    acceleration is 9.8 (gravity) because it was falling.
    time is 3.03

    0 + (3.03 x 9.8) = final velocity

    the average velocity is your final velocity plus your initial velocity divided by 2
    which is just your final velocity divided by 2 because your initial velocity was zero.

    how high is the bridge?
    distance the object fell= average velocity x time

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  2. thank you very much

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  3. why u divide the final velocity by 2?

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  4. ahaaaaaa i understand

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  5. could u give me the answers for check please

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