2g NaHCO3 + .6 mL HCL --> NaCl+CO2+H2O
How much carbon dioxide do I get? How do I find out?
A worked example. Just follow the steps. Remember moles = M x L and/or moles = grams/molar mass. Post your work if you get stuck.
http://www.jiskha.com/science/chemistry/stoichiometry.html
To find out how much carbon dioxide (CO2) is produced in the reaction, you need to use stoichiometry. Stoichiometry is a method used to determine the quantities of reactants and products in a chemical reaction.
In this case, you have the balanced chemical equation:
2 NaHCO3 + HCl → 2 NaCl + CO2 + H2O
The equation tells us that for every 2 moles of NaHCO3, 1 mole of CO2 is produced.
To find the amount of CO2 produced, you need to know the amount of NaHCO3 reacted. In your question, you have mentioned 2g of NaHCO3.
1. Convert the mass of NaHCO3 to moles:
- The molar mass of NaHCO3 (sodium bicarbonate) is approximately 84 g/mol.
- Use the formula: moles = mass / molar mass
- moles of NaHCO3 = 2g / 84 g/mol = 0.024 moles
2. Apply stoichiometry to determine moles of CO2:
- According to the balanced equation, 2 moles of NaHCO3 react to produce 1 mole of CO2.
- Therefore, the moles of CO2 produced are also 0.024 moles.
3. Convert moles of CO2 to mass:
- The molar mass of CO2 (carbon dioxide) is approximately 44 g/mol.
- Use the formula: mass = moles × molar mass
- mass of CO2 = 0.024 moles × 44 g/mol = 1.056 grams
Therefore, you will get approximately 1.056 grams of CO2 produced in the reaction.