A circle is centered at (2, -5) and has radius 3. Write its equation in standard form.
for a given centre of (h,k) and radius r, the equation is
(x-h)^2 + (y-k)^2 = r^2
use your information to form the equation.
(x-2)^2+[y-(-5)]^2=r^2
(x-2)^3+(y+5)^2=3^2
(x-2)^3+(y+5)^2=9
To write the equation of a circle in standard form, we need to know the center coordinates (h, k) and the radius (r) of the circle.
Given that the circle is centered at (2, -5) and has a radius of 3, we can use the standard form equation of a circle, which is:
(x - h)^2 + (y - k)^2 = r^2
Substituting the values of the center coordinates and radius:
(x - 2)^2 + (y - (-5))^2 = 3^2
Simplifying:
(x - 2)^2 + (y + 5)^2 = 9
Therefore, the equation of the circle in standard form is (x - 2)^2 + (y + 5)^2 = 9.