Math (Statistics)

You and three of your friends are part of a group of 10 potential jurors. What is the probability that you and your 3 friends are the last 4 people chosen?

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  1. Suppose the names of you and your 3 friends are
    A, B, C, and D
    and X is anybody else

    so one correct order of choosing would be
    XXXXXXABCD
    but the order of ABCD could be arranged in 4! or 24 ways

    the prob of XXXXXXABCD
    = (6/10)(5/9)(4/8)(3/7)(2/6)(1/5)(1/4)(1/3)(1/2)(1/1) = 6!/10!

    but there are 24 of these
    prob of your event = 24(6!/10!) = appr. .00476

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