What is the volume of 0.05-molar HCl that is required to neutralize 50 ml of a 0.10-molar Mg(OH)2 solution?

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  1. Mg(OH)2 + 2HCl ==> MgCl2 + 2H2O
    mols Mg(OH)2 = M x L = ??
    moles HCl = 2x that (Look at the coefficients in the balanced equation.)
    M HCl = mols HCl/L HCl
    Substitute and solve for L HCl.

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  2. 0.05 L

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