When a solution is diluted with water, the ratio of the initial to final volumes of solution is equal to the ratio of final to initial molarities.
true or false?
screw you DrBob222 just say true or false
Say we want to dilute a 1 M solution from 10 to 100 mL. The final concn will be
1M x (10/100) = 0.1M
10 is initial volume.
100 is final volume
1M = initial M
0.1M is final M
So plug in the numbers from the example problem I've worked and see if the statement is true or false.
True.
When a solution is diluted with water, the ratio of the initial volume of the solution to the final volume of the solution is equal to the ratio of the final molarity to the initial molarity. This relationship is known as the dilution equation and is given by the formula:
M1V1 = M2V2
Where M1 is the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume.
So, if we rearrange this equation, we get:
V1 / V2 = M2 / M1
Therefore, the statement is true.
True.
Explanation:
When a solution is diluted with water, the ratio of the initial volume of the solution to the final volume of the solution is equal to the ratio of the final molarity of the solution to the initial molarity. This statement is known as the dilution formula or the "m₁v₁ = m₂v₂" equation, where:
- m₁ is the initial molarity (concentration) of the solution
- v₁ is the initial volume of the solution
- m₂ is the final molarity (concentration) of the solution
- v₂ is the final volume of the solution
This formula is derived from the concept of conservation of moles. When a solution is diluted, the total number of moles of solute remains unchanged. Therefore, the initial moles of solute (m₁v₁) must be equal to the final moles of solute (m₂v₂). Dividing both sides of the equation by m₁v₂ gives the ratio:
m₁v₁ / m₁v₂ = m₂v₂ / m₁v₂
which simplifies to:
v₁ / v₂ = m₂ / m₁
This means that the ratio of the initial volume to the final volume is equal to the ratio of the final molarity to the initial molarity when a solution is diluted with water.