calculate the volume in milliliters of 3.6 mol/L sodium nitrate solution that contains 325 mmol of sodium nitrate
Since L x M = moles, then
mL x M = mmoles.
Substitute and solve for mL.
To calculate the volume in milliliters (mL) of a solution, we can use the formula:
Volume (mL) = Amount of solute (mol) / Concentration (mol/L) * 1000
Given:
Amount of sodium nitrate = 325 mmol
Concentration of sodium nitrate solution = 3.6 mol/L
First, we need to convert the amount of sodium nitrate from millimoles (mmol) to moles (mol):
Amount of sodium nitrate (mol) = 325 mmol / 1000 = 0.325 mol
Now, we can calculate the volume using the formula:
Volume (mL) = 0.325 mol / 3.6 mol/L * 1000 = 90.28 mL
Therefore, the volume of the 3.6 mol/L sodium nitrate solution containing 325 mmol of sodium nitrate is approximately 90.28 mL.