tan 0=1
csc 0 = sqrt. 2
cos 0 = sin 0
os 0 = cos (-pie/6)

The 0s means that symbol for angle. Please someone help me do these problems.

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  1. What is the interval of theta for which they want the answers? 0 to 2 pi?

    tan theta = 1 at theta = pi/4 (45 degrees) and (in the third quadrant) at 5 pi/4

    csc theta = sqrt 2 where sin theta = 1/sqrt2 which is also at pi/4, with a second-quadrant solution at 3 pi/4

    cos theta = sin theta where tan theta = 1. Refer to the first answer

    If your last question is
    cos theta = cos -pi/6,
    one obvious solution is
    theta = -pi/6,
    which would be the same as 11 pi/6 in the 0 to 2pi range. The other answer would be just pi/6 in the first quadrant, where the cosine has the same positivee sign as the fourth quadrant.

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  2. thanks, yes sorry the interval was 0 to 2pie

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