algebra

How would one write the equation of a parabola whose directrix is y=-6 and location of the focus is (-3,2)

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  1. F(-3,2)

    V(-3,K)

    D(-3,-6)

    DV = VF,
    K-(-6) = 2 - K,
    K + 6 = 2 - K,
    2K = 2 - 6 = -4,
    K = -2.

    V(-3,-2)

    1/4a = DV = VF,
    1/4a = 2-K,
    1/4a = 2 - (- 2),
    1/4a = 4,
    16a = 1,
    a = 1/16.

    Y = a(x-h)^2 + k,
    Eq: Y = 1/16(x+3)^2 -2. Vertex Form.

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