math
 👍 0
 👎 0
 👁 1,207

 👍 0
 👎 0
Respond to this Question
Similar Questions

Calculus
The line that is normal to the curve x^2=2xy3y^2=0 at(1,1) intersects the curve at what other point? Please help. Thanks in advance. We have x2=2xy  3y2 = 0 Are there supposed to be 2 equal signs in this expression or is it x2 +

Calculus
Consider the curve defined by y + cosy = x +1 for 0 =< y =< 2pi.... a. Find dy/dx in terms of y. *I got 1/(ysiny) but I feel like that's wrong. b. Write an equation for each vertical tangent to the curve. c. find d^2y/dx^2 in

Ap calc.. Dying!! Please help!
Given the curve x^2xy+y^2=9 A) write a general expression for the slope of the curve. B) find the coordinates of the points on the curve where the tangents are vertical C) at the point (0,3) find the rate of change in the slope

Calc
Consider the following. cos(x) + sqrt(y)= 1 (a) Find y' by implicit differentiation. y' = 2y^(1/2) sin(x) Correct: Your answer is correct. (b) Solve the equation explicitly for y and differentiate to get y' in terms of x. y' = ?

calculus
Using 4x^2  9y^2 = 36 Find y by implicit differentiation and then solve the equation explicitly for y and differentiate to get y' in terms of x.

calculus
1. Given the curve a. Find an expression for the slope of the curve at any point (x, y) on the curve. b. Write an equation for the line tangent to the curve at the point (2, 1) c. Find the coordinates of all other points on this

Calculus
Find dy/dx by implicit differentiation: x^22xy+y^3 = c Thank you!

calculus
Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x2 + 2xy − y2 + x = 17, (3, 5) (hyperbola)

last calc question, i promise!
given the curve x + xy + 2y^2 = 6... a. find an expression for the slope of the curve. i got (1y)/(x + 4y) as my answer. b. write an equation for the line tangent to the curve at the point (2,1). i got y = (1/3)x + (5/3). but i

calculus
A. find y' by implicit differentiation. B. solve th equation explicitly for y and differentiate to get y' in terms of x. cos (x) + √y = 5

Calculus
Consider the following. cos(x) + sqrt(y)= 1 (a) Find y' by implicit differentiation. y' = Correct: Your answer is correct. (b) Solve the equation explicitly for y and differentiate to get y' in terms of x. y' = ? (c) Check that

calculus
Find all points on the curve x^2y^2+xy=2 where the slope of tangent line is 1. This is what I got. x^2y^2+xy=2 x^2*2ydy/dx + 2x*y^2 + x*dy/dx + y =0 dy/dx(2yx^2+x)= 2xy^2y dy/dx = (2xy^2y)/(x+2yx^2) how do I finish from here?
You can view more similar questions or ask a new question.