How much water do you need to add to 10 mL of a solution of HCl with a pH of 3 to change the pH to 6?

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  1. pH = 3, (H^+) = 1E-3
    pH = 6, (H^+) = 1E-6

    So how much dilution is required?
    1 x 10E-3*(10 mL/X mL) = 1E-6
    Solve for X. I get something like 10,000 mL so you would need to add 10,000-10 = ??

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