If 15.0ml of a 6.0M HCl solution is diluted to 75.00ml, what is the molarity of the diluted solution?
To find the molarity (M) of the diluted solution, you can use the equation
M1V1 = M2V2
where M1 is the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume.
In this case, the initial volume (V1) is 15.0 mL and the initial molarity (M1) is 6.0 M. The final volume (V2) is 75.00 mL, and we want to find the final molarity (M2).
Plugging the values into the equation, we have:
(6.0 M)(15.0 mL) = M2(75.00 mL)
Now let's solve for M2:
(6.0 M)(15.0 mL) = M2(75.00 mL)
90.0 mL∙M = 75.00 mL∙M2
To isolate M2, we can divide both sides of the equation by 75.00 mL:
(90.0 mL∙M) / 75.00 mL = M2
Simplifying the equation:
M2 = 1.2 M
Therefore, the molarity of the diluted solution is 1.2 M.