# physics

5. A tin nucleus has charge +50e. Find the potential V at a distance of 10-12 meters from the nucleus and the potential energy U of a proton at this position. The proton has charge
+e = 1.6 x 10-19 C

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1. V = k Q /r which is the potential energy of a charge of one coulomb at distance r from charge Q

V = (9*10^9)(50*1.6*10^-19) / 10^-12

U = q V = 1.6*10^-19 * V

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3. Madarchod pura solve kar behenchod

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