How do I find how many grams of CH3COOH are present in cm^3 of vinegar? Also, how many moles of CH3COOH are present in 2.5 cm^3 of vinegar? Thanks!
use the formula moles=concentration x volume
and moles=mass/Mr
To find the number of grams of CH3COOH present in a given volume of vinegar (in cm^3), you will need to know the density of vinegar and the concentration of CH3COOH in vinegar.
1. First, obtain the density of vinegar. You can usually find this information on the vinegar bottle or by searching online. Let's say the density of vinegar is 1.01 g/cm^3.
2. Next, determine the concentration of CH3COOH in vinegar. This is usually reported as a percentage. For example, if the concentration is 5% (common for household vinegar), it means there are 5 grams of CH3COOH in every 100 grams of vinegar.
3. Calculate the amount of CH3COOH in grams using the following formula:
Grams of CH3COOH = Volume of vinegar (in cm^3) x Density of vinegar (in g/cm^3) x Concentration of CH3COOH (%)
For example, if you have 10 cm^3 of vinegar with a density of 1.01 g/cm^3 and a concentration of 5%:
Grams of CH3COOH = 10 cm^3 x 1.01 g/cm^3 x 5/100
Grams of CH3COOH = 0.505 grams
To find the number of moles of CH3COOH in a given volume of vinegar (in cm^3), you will need to know the molar mass of CH3COOH in addition to the previous information.
4. Determine the molar mass of CH3COOH. The molar mass is the sum of the atomic masses of the elements in the compound. For CH3COOH, the molar mass is approximately 60.05 g/mol.
5. Calculate the number of moles of CH3COOH using the following formula:
Moles of CH3COOH = Grams of CH3COOH / Molar mass of CH3COOH
For example, if you have 2.5 cm^3 of vinegar with a density of 1.01 g/cm^3, a concentration of 5% and we previously calculated that it contains 0.505 grams of CH3COOH:
Moles of CH3COOH = 0.505 grams / 60.05 g/mol
Moles of CH3COOH = 0.0084 moles
Therefore, in 2.5 cm^3 of vinegar, there are approximately 0.505 grams of CH3COOH and 0.0084 moles of CH3COOH.