Algebra 2

how do you graph the function?
f(x)=2(x+2)^2(x+4)^2

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  1. visualize the function as
    f(x) = 2(x+2)(x+2)(x+4)(x+4)
    which would make it a fourth degree function.
    Fourth degree functions tend to look like a "W" in their general form, anyway they "rise" into the first and second quadrants.

    notice there are double roots at x=-2 and x=-4, so the curve 'touches' the x-axis at -2 and -4 without crossing

    What does it do between -2 and -4?
    Try x=-3, f(-3) = 2
    try f(0), you get f(0) = 128

    Can you see the "W" ?

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