chemistry

2Sb + 3I2->2SbI3
Determine the limiting reactant and theoretical yield when 1.2 mol of Sb and 2.40 mol I2 are mixed.

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  1. There are shorter ways of doing this but I like the following method.
    Convert 1.2 mol Sb to mols SbI3.
    Convert 2.4 mol I2 to mols SbI3.
    The smaller number will be the correct one and that will be the limiting reagent. The theoretical yield will be that number of mols SbI3 x molar mass SbI3.
    Post your work if you need more help.

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