math-triangle help

I need help with this:

Given a right triangle with B=4 and
C=11 find A appoximated to three decimal places.

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  1. Use the Pythagorean theorem, r^2 = y^2 + x^2

    r^2
    = 4^2 + 11^2
    = 16 + 121
    = 137
    = Square root of 137
    = 11.705

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  2. This is how I would do it.

    Pythagorean theorem: a2 + b2 = c2.

    a^2 + 4^2 = 11^2

    a^2 +16 = 105
    subtract both sides by 16
    a^2 - 16 = 105 - 16
    a^2 = 105
    a = sqrt 105
    a = 10.247

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