How much heat is required to convert 0.4 kilograms of ice at 0 degrees celsius to water at the same temperature?
q = 400 g x heat fusion water.
To calculate the amount of heat required to convert ice at 0 degrees Celsius to water at the same temperature, we can use the formula:
Q = m * L
Where:
Q is the amount of heat required in joules (J),
m is the mass of the substance in kilograms (kg), and
L is the latent heat of fusion for the substance in joules per kilogram (J/kg).
In this case, since we are converting ice to water at the same temperature, we are dealing with the latent heat of fusion. The latent heat of fusion for ice is 334,000 J/kg.
Given:
m = 0.4 kg (mass of ice)
Now we can calculate the amount of heat required to convert the ice to water:
Q = 0.4 kg * 334,000 J/kg
Q = 133,600 J
Therefore, 133,600 joules of heat is required to convert 0.4 kilograms of ice at 0 degrees Celsius to water at the same temperature.